Answer
Given, 3 sin θ + 5 cos θ = 5 –i)
Let, 5 sin θ – 3 cos θ =x –ii)
Squaring and adding (i) and (ii) we get,
=>$$34(sin^2θ+cos^2θ)=25+x^2$$
=> $$34=25+x^2$$
=> x = ±3,
Hence from the option we get -3
Answer – (B)
Given, 3 sin θ + 5 cos θ = 5 –i)
Let, 5 sin θ – 3 cos θ =x –ii)
Squaring and adding (i) and (ii) we get,
=>$$34(sin^2θ+cos^2θ)=25+x^2$$
=> $$34=25+x^2$$
=> x = ±3,
Hence from the option we get -3
Answer – (B)