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Question

3 (sin x – cos x)^4 + 6 (sin x + cos x)^2+4 (sin x)^6 + 4 (cos x)^6
equals to

  1. 9
  2. 11
  3. 13
  4. 15
Answer

=3 (sin x – cos x)^4 + 6 (sin x + cos x)^2+4 (sin x)^6 + 4 (cos x)^6 

=3{sin^2x+cos^2x-2sinxcosx}^2+6(sin^2x+cos^2x+2sinxcosx)+4sin^6x+4cos^6x

=3{1-2sinxcosx}^2+6(1+2sinxcosx)+ 4sin^6x+4cos^6x

=3{1+4sin^2xcos^2x-4sinxcosx}+6(1+2sinxcosx)+4sin^6x+4cos^6x

=3+12sin^2xcos^2x-12 sinx cosx+6+12 sinx cosx+4sin^6x+4cos^6x

=3+12sin^2xcos^2x-12 sinx cosx+6+12 sinx cosx+4((sin^2x)^3+(cos^2x)^3)

=3+12sin^2xcos^2x-12 sinx cosx+6+12 sinx cosx+4(sin^2x+cos^2x)^3-3sin^2xcos^2x(sin^2x+cos^2x

=3+12sin^2xcos^2x-12 sinx cosx+6+12 sinx cosx+4(sin^2x+cos^2x)^3-12sin^2xcos^2x

=3+6+4 =13

Answer (C)

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