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Question

What is the HCF ofacx³ + bcx² + adx² + acdx + bdx + bcd and adx³ + acx² + bdx² + bcx + acdx + bcd if HCF (c, d) = 1, c ≠ d?

  1. bx+c
  2. cx+d
  3. ax+d
  4. ax+b
Answer

acx³ + bcx² + adx² + acdx + bdx + bcd    —-(i)

adx³ + acx² + bdx² + bcx + acdx + bcd     ––(ii)

 For equation (i),

     acx³ +adx²+acdx + bcx² + bdx + bcd

       ax(cx^2+dx+cd) + b(cx^2+dx+cd)

    (ax+b)(cx^2+dx+cd)


 For equation (ii),

   adx³ + acx² + bdx² + bcx + acdx + bcd

   adx³ + acx² +acdx + bdx² + bcx + bcd

      ax(dx^2+cx+cd) + b(dx^2+cx+cd)

   (ax+b)(dx^2+cx+cd)

So, HCF is ( ax + b ). 

Answer (D) – ax+b

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